Max. no of lags per output product (or channel) =
16*1024
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{log_3(N_level)}^2 * N_interleave * N_output_products]
N_level is 3 or 9 [i.e. log_3(N_level) is 1 or 2 respectively];
N_interleave is 1 (for BW <= 50 MHz) or 2 for 100 MHz BW;
N_output_products is 1 or 2 (channel autocorrs) or 4 (Stokes);
& log_3() indicates log to the base 3.
The best resolution for a 100MHz bands, using 16 bits/lag, and summing the polarizations are given by the formulas,
#lags = (i - 1)* 6.25, where i = integration time in usecs
Data rate to disk = 12MBytes/s; Resolution = 100MHz/#lags
| Integration time | Max lags | Resolution |
|---|---|---|
| 100us | 616 | 162kHz |
| 64us | 392 | 255kHz |
| 32us | 192 | 520kHz |
2 channels,continuous sampling
| Bandwidth(MHz) | Data Rate Mbyte/s | Bit Packing |
|---|---|---|
| 50 | 25 | 1 |
| 25 | 25 | 2 |
| 12.5 | 25 | 4 |
| 6.25 | 12.5 | 4 |
| 3.125 | 6.25 | 4 |
| 1.56 | 3.12 | 4 |
| 0.78 | 1.56 | 4 |
| 0.390 | 0.78 | 4 |
| 0.195 | 0.39 | 4 |